Basic Electrical Engineering MCQs Part 16
Contents
- 1 Electric current in a discharge tube containing gas is due which of following
- 2 At 0 K Germanium behaves as
- 3 Two resistors X and Y having resistance value Rx and Ry having resistivities ρx and ρy. If Rx < Ry, then
- 4 For a 10 kΩ resistor, the change in voltage when current changes from 2 mA to 5.5 mA is
- 5 A carbon electrode has resistance of 0.12 Ω at 20°C. The temperature coefficient of carbon is -0.0005 at 20 °C. The value of resistance of electrode at 85°C is
Electric current in a discharge tube containing gas is due which of following
Electric current in a discharge tube containing gas is due which of following:
- Positive ions only
- Electrons only
- Electrons and positive ions
- None of these
Correct answer: 3. Electrons and positive ions
At 0 K Germanium behaves as
At 0 K Germanium behaves as:
- Conductor
- Insulator
- Ferromagnetic
- Super conductor
Correct answer: 2. Insulator
Two resistors X and Y having resistance value Rx and Ry having resistivities ρx and ρy. If Rx < Ry, then
Two resistors X and Y having resistance value Rx and Ry having resistivities ρx and ρy. If Rx < Ry, then:
- Ρx = ρy
- ρx < ρy
- ρx > ρy
- Insufficient data
Correct answer: 4.Insufficient data
For a 10 kΩ resistor, the change in voltage when current changes from 2 mA to 5.5 mA is
For a 10 kΩ resistor, the change in voltage when current changes from 2 mA to 5.5 mA is:
- 35 V
- 50 V
- 70 V
- 120 V
Correct answer: 1. 35 V
Solution:
For resistor, the voltage versus current graph is linear.
When I = 2 mA; V = 20 V
When I = 5.5 mA; V = 55 V
Change in voltage = 55 V – 20 = 35 V
A carbon electrode has resistance of 0.12 Ω at 20°C. The temperature coefficient of carbon is -0.0005 at 20 °C. The value of resistance of electrode at 85°C is
A carbon electrode has resistance of 0.12 Ω at 20°C. The temperature coefficient of carbon is -0.0005 at 20 °C. The value of resistance of electrode at 85°C is:
- 0.1161
- 0.3255
- 0.9898
- 1.234
Correct answer: 1. 0.1161
Solution:
R2 = R1 [ 1 + α(t 2- t1)]
R2 = 0.12 (1 + -0.0005 * (85 – 20))
R2 = 0.1161 Ω