Electrical Engineering MCQs on Capacitance
Four capacitors of 0.15 µF are connected in parallel. The total capacitance is:
- 0.0375 µF
- 0.0658 µF
- 0.159 µF
- 0.309 µF
Correct answer: 1. 0.0375 µF
Explanation:
Formula for parallel capacitors:
1/CT = 1/C1 + 1/C2 + 1/C3 + 1/C4
CT = 0.0375 µF