Electrical Engineering MCQ
If the primary fault current is 2000 A, the relay setting is 50% and CT ratio is 400 : 5, then plug setting multiplier will be:
- 5
- 20
- 30
- 10
Current answer: 4. 10
Explanation:
Pick up Value = Rated secondary current of CT × Current Setting
= 5 × 0.5 = 2.5 A
Fault current in relay coil = 2000 × 5/400 = 25 A
Plug setting Multiplier = Fault current in relay coil/Pick up value
= 25/2.5 = 10