Power Generation MCQs Part 18
Contents
- 1 Nuclear reactors utilize the process of
- 2 A diesel station supplies following loads to various consumers
- 3 Mechanical energy is supplied to a DC generator at rate of 5000 J/s. The generator delivers 40 at 110 V. The efficiency of generator is:
- 4 Certain power station has an average demand of 15 MW. If plant capacity factor is 50% and load factor is 60%. The reserve capacity of plant is:
- 5 Generally, It is a practice to keep capacity of power plant by XYZ percentage more than maximum demand for meeting future load requirements:
Nuclear reactors utilize the process of
Nuclear reactors utilize the process of:
- Fission
- Fusion
- Both of these
- None of these
Correct answer: 1. Fission
A diesel station supplies following loads to various consumers
A diesel station supplies following loads to various consumers:
Industrial consumers = 2000
Domestic power = 150
Commercial load = 800
Domestic lighting load = 400 kW
If maximum demand on station is 3200 kW. Then diversity factor is:
- 0.94
- 0.97
- 1.02
- 1.05
Correct answer: 4. 1.05
Solution:
Diversity factor = (2000 + 150 + 800 + 400)/3200 = 1.05
Mechanical energy is supplied to a DC generator at rate of 5000 J/s. The generator delivers 40 at 110 V. The efficiency of generator is:
Mechanical energy is supplied to a DC generator at rate of 5000 J/s. The generator delivers 40 at 110 V. The efficiency of generator is:
- 92%
- 88%
- 84%
- 80%
Correct answer: 2. 88%
Solution:
Input power = 5000 J/s = 5000 W
————–
Output power (Po) = 110 * 40 = 4400 W
————–
Efficiency (η) = Po/Pi * 100 = 4400/5000*100 = 88%
Certain power station has an average demand of 15 MW. If plant capacity factor is 50% and load factor is 60%. The reserve capacity of plant is:
Certain power station has an average demand of 15 MW. If plant capacity factor is 50% and load factor is 60%. The reserve capacity of plant is:
- 2 MW
- 5 MW
- 15 MW
- 25 MW
Correct answer: 2. 5 MW
Solution:
From formula of Plant capacity factor
Plant capacity factor = Average demand/Plant capacity
Plant capacity = Average demand/Plant capacity factor = 15/0.5 = 30 MW
——————-
Maximum demand = Average demand/Load factor = 15/0.6 = 25 MW
——————-
Reserve capacity of plant = Plant capacity – Max.demand = 30 – 25 = 5 MW
Generally, It is a practice to keep capacity of power plant by XYZ percentage more than maximum demand for meeting future load requirements:
Generally, It is a practice to keep capacity of power plant by XYZ percentage more than maximum demand for meeting future load requirements:
- 15 to 20%
- 45 to 50%
- 65 to 70%
- 90 to 95%
Correct answer: 1. 15 to 20%