Electrical Engineering MCQ on Capacitance
The capacitive reactance of a 0.47 µF capacitor that is across a 2 kHz sine wave signal source:
- 1.7 Ω
- 17.5 Ω
- 140 Ω
- 170 Ω
Correct answer: 4. 170 Ω
Explanation
Formula for capacitive reactance
Xc = 1/ωC=1/2πfC = 1/(2π * 2 kHz * 0.47 µF) = 169.31 ≈ 170 Ω